 | Euclides - 1855 - 270 páginas
...and there are as many triangles in the figure as it has sides, all the angles of these triangles are equal to twice as many right angles as the figure has sides. But all the angles of these triangles are equal to the interior angles of the figure, viz. ABС, BСD,... | |
 | Charles Davies - 1855 - 340 páginas
...triangles is equal to two right angles (Th- xvii) : hence, the sum of the angles of all the triangles is equal to twice as many right angles as the figure has sidesBut the sum of all the angles about the point P is equal to four right angles (Th- ii- Cor- 4)... | |
 | William Mitchell Gillespie - 1856 - 478 páginas
...subject. It is a well-known proposition of Geometry, that in any figure bounded by straight lines, the sum of all the interior angles is equal to twice...as many right angles, as the figure has sides less two ; since the figure can be divided into that number of triangles. Hence this common rule. " Calculate... | |
 | George Roberts Perkins - 1856 - 460 páginas
...has sides ; but the sum of all the exterior angles is equal to four right angles (T. IV.) ; therefore the sum of all the interior angles is equal to twice as many right angles as the polygon has sides, wanting four right angles. Cor. I. In any triangle, the sum of the three angles... | |
 | Euclides - 1856 - 168 páginas
...with four right angles. Therefore all the angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides. XVI. If two triangles have two sides of the one equal to two sides of the other, each to each, and... | |
 | Henry James Castle - 1856 - 220 páginas
...angles are the exterior angles of an irregular polygon ; and as the sum of all the interior angles are equal to twice as many right angles, as the figure has sides, wanting four ; and as the sum of all the exterior, together with all the interior angles, are equal... | |
 | Cambridge univ, exam. papers - 1856 - 200 páginas
...Prove that all the internal angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides; and that all the external angles are together equal to four right angles. In what sense are these propositions... | |
 | Frederick Walter Simms - 1856 - 258 páginas
...together all the internal angles, marked by dotted segments of circles; and subtract their sum from twice as many right angles as the figure has sides, less four, for the angle db e. Example. — Let the angles denoted by the dotted segments at the different letters... | |
 | Sir Norman Lockyer - 1880 - 668 páginas
...XXVI. of the syllabus, that the interior angles of any polygon, together with four right angles, are equal to twice as many right angles as the figure has sides. In the new notation we would say that the sum of the interior angles of the polygon is equal to a number... | |
 | John Henry Robson - 1880 - 116 páginas
...proved that " All the Interior angles of any Rectilineal figure, "together with four right angles, are equal to "twice as many right angles as the figure has " sides." If, therefore, we suppose the polygon to have n sides, All its interior angles + 4.90 .= 272.90 . -.... | |
| |
All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides. 
