Elementary Geometry ... |
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Página 7
... placed , lie wholly on any other part , if its extremi- ties are made to fall on that other part . Def . 6. A plane surface , or plane , is a surface in which any two points being taken the straight line that joins them lies wholly in ...
... placed , lie wholly on any other part , if its extremi- ties are made to fall on that other part . Def . 6. A plane surface , or plane , is a surface in which any two points being taken the straight line that joins them lies wholly in ...
Página 9
... placed between letters at points on each of its arms , as BAC , or CAB . Def . 12. When three straight lines are drawn from a point , if one of them be regarded as lying between the other two , the angles which this one ( the mean ) ...
... placed between letters at points on each of its arms , as BAC , or CAB . Def . 12. When three straight lines are drawn from a point , if one of them be regarded as lying between the other two , the angles which this one ( the mean ) ...
Página 12
... ; it is required to prove that ABC is equal to PRS . Proof . If the point B were placed on the point R , and the line BC along the line RS , then because the lines DC , QS are ' straight 12 [ Book I. ELEMENTARY GEOMETRY .
... ; it is required to prove that ABC is equal to PRS . Proof . If the point B were placed on the point R , and the line BC along the line RS , then because the lines DC , QS are ' straight 12 [ Book I. ELEMENTARY GEOMETRY .
Página 19
... placed on the point D , and the line AB were placed along DE , then because the angle BAC = the angle EDF , ( Hyp . ) therefore the line AC would lie along DF . And because AB = DE , ( Hyp . ) therefore the point B would coincide with ...
... placed on the point D , and the line AB were placed along DE , then because the angle BAC = the angle EDF , ( Hyp . ) therefore the line AC would lie along DF . And because AB = DE , ( Hyp . ) therefore the point B would coincide with ...
Página 21
... placed on the point E , and the line BC along the line EF ; then because BC = EF , ( Hyp . ) therefore the point C would fall on F. And because the angle B = the angle E , ( Hyp . ) therefore the line BA would fall along the line ED ...
... placed on the point E , and the line BC along the line EF ; then because BC = EF , ( Hyp . ) therefore the point C would fall on F. And because the angle B = the angle E , ( Hyp . ) therefore the line BA would fall along the line ED ...
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Términos y frases comunes
AB² ABCD alternate angles angle ABC angle APB angle BAC angles are equal angles equal bisector centre chord circumference coincide College Constr construct contrapositive Crown 8vo describe a circle diagonals diameter divided draw Edition equal angles equal circles equiangular Euclid exterior angle fcap Find the locus four right angles Geometry given angle given circle given line given point given rectilineal figure given straight line hypotenuse included angle inscribed intersect isosceles triangle less Let AB Let ABC locus magnitudes meet middle point minor arc opposite angles opposite sides parallel parallelogram perpendicular polygon PROBLEM produced Proof Q. E. D. THEOREM quadrilateral radius rectangle contained reflex angle required to prove rhombus right angles segment semicircle Shew square subtend supplementary supplementary angles tangent THEOREM trapezium triangle ABC triangles are equal unequal
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