Elementary Geometry ... |
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Página 8
... diameter of a circle is a straight line drawn through the centre and terminated both ways by the circum- ference . Def . II . When two straight lines are drawn from the same point , they are said to contain , or to make with each other ...
... diameter of a circle is a straight line drawn through the centre and terminated both ways by the circum- ference . Def . II . When two straight lines are drawn from the same point , they are said to contain , or to make with each other ...
Página 11
... , τí☺ŋμi . Identity . Idem , identidem , the same thing . Geometry . n , μeтpéw , to measure land . Diameter . did μerpéw , to measure across . Plane . Planus , level . Complement . Compleo , BOOK I. ] II GEOMETRICAL AXIOMS .
... , τí☺ŋμi . Identity . Idem , identidem , the same thing . Geometry . n , μeтpéw , to measure land . Diameter . did μerpéw , to measure across . Plane . Planus , level . Complement . Compleo , BOOK I. ] II GEOMETRICAL AXIOMS .
Página 102
... diameter describe a semicircle , U being the centre , and produce RQ to meet the circumference in V. If a square be described on QV , this square will be equal to ABCDE . - Proof . For since PQ is the sum of PU and UQ , and QT is the ...
... diameter describe a semicircle , U being the centre , and produce RQ to meet the circumference in V. If a square be described on QV , this square will be equal to ABCDE . - Proof . For since PQ is the sum of PU and UQ , and QT is the ...
Página 108
... diameters of the rhombus . 18. If two opposite sides of a quadrilateral are paral- lel , and their points of bisection joined , the quadrilateral will be bisected . 19. If two opposite sides of a parallelogram be bi- sected , and lines ...
... diameters of the rhombus . 18. If two opposite sides of a quadrilateral are paral- lel , and their points of bisection joined , the quadrilateral will be bisected . 19. If two opposite sides of a parallelogram be bi- sected , and lines ...
Página 111
... diameter of two concentric circles , P , Q any points on the outer and inner circles respectively . Prove that BP + CP2 = AQ3 + DQ3 . 47. Given a polygon of n sides to construct an equal polygon of ( n - 1 ) sides . Hence construct a ...
... diameter of two concentric circles , P , Q any points on the outer and inner circles respectively . Prove that BP + CP2 = AQ3 + DQ3 . 47. Given a polygon of n sides to construct an equal polygon of ( n - 1 ) sides . Hence construct a ...
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Términos y frases comunes
AB² ABCD alternate angles angle ABC angle APB angle BAC angles are equal angles equal bisector centre chord circumference coincide College Constr construct contrapositive Crown 8vo describe a circle diagonals diameter divided draw Edition equal angles equal circles equiangular Euclid exterior angle fcap Find the locus four right angles Geometry given angle given circle given line given point given rectilineal figure given straight line hypotenuse included angle inscribed intersect isosceles triangle less Let AB Let ABC locus magnitudes meet middle point minor arc opposite angles opposite sides parallel parallelogram perpendicular polygon PROBLEM produced Proof Q. E. D. THEOREM quadrilateral radius rectangle contained reflex angle required to prove rhombus right angles segment semicircle Shew square subtend supplementary supplementary angles tangent THEOREM trapezium triangle ABC triangles are equal unequal
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