Mathematical Problems on the First and Second Divisions of the Schedule of Subjects for the Cambridge Mathematical Tripos ExaminationMacmillan and Company, 1878 - 480 páginas |
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Página xii
... inclined at a given angle are drawn touching respectively two given concentric circles : their point of intersection will lie on one of two fixed circles concentric with the given circles . 14. A chord CD is drawn at right angles to a ...
... inclined at a given angle are drawn touching respectively two given concentric circles : their point of intersection will lie on one of two fixed circles concentric with the given circles . 14. A chord CD is drawn at right angles to a ...
Página 1
... inclined at a constant angle . 27. If two circles touch at A and PQ be any chord of one circle touching the other , the sum or the difference of the chords AP , AQ will bear to the chord PQ a constant ratio . 28. Four points A , B , C ...
... inclined at a constant angle . 27. If two circles touch at A and PQ be any chord of one circle touching the other , the sum or the difference of the chords AP , AQ will bear to the chord PQ a constant ratio . 28. Four points A , B , C ...
Página 2
... inclined to the bisector of the angle 4 and will coincide with this bisector when the given ratio has its least possible value , which is when O'O is to 40 in the duplicate ratio of BC to the sum of the other two sides . Also the ...
... inclined to the bisector of the angle 4 and will coincide with this bisector when the given ratio has its least possible value , which is when O'O is to 40 in the duplicate ratio of BC to the sum of the other two sides . Also the ...
Página 115
... inclined to the tangents drawn to B from the same point . 643. In a parabola AQ is drawn through the vertex A at right angles to a chord AP to meet the diameter through P in Q : prove that Q lies on a fixed straight line . 614. Through ...
... inclined to the tangents drawn to B from the same point . 643. In a parabola AQ is drawn through the vertex A at right angles to a chord AP to meet the diameter through P in Q : prove that Q lies on a fixed straight line . 614. Through ...
Página 118
... inclined at an angle of 120 " : prove that a tangent to either curve at a common point will meet the other in a point of contact of a common tangent . 673. The chord PR is normal at P , O is the centre of curvature at P and U the pole ...
... inclined at an angle of 120 " : prove that a tangent to either curve at a common point will meet the other in a point of contact of a common tangent . 673. The chord PR is normal at P , O is the centre of curvature at P and U the pole ...
Otras ediciones - Ver todas
Mathematical Problems on the First and Second Divisions of the Schedule of ... Joseph Wolstenholme Sin vista previa disponible - 2012 |
Mathematical Problems: On the First and Second Divisions of the Schedule of ... Joseph Wolstenholme Sin vista previa disponible - 2017 |
Términos y frases comunes
angular points angular velocity asymptotes ax² axes bisected cardioid centre of perpendiculars chord circumscribed circle co-ordinates common point common tangents confocal conicoid conjugate diameters constant continued fraction cos² curve described diagonals directrix envelope equal excentric angles fixed circle fixed point fixed straight line foci focus four points given circle given conic given ellipse given point given the equations inscribed latus rectum length locus major axis meet minor axis normal parabola parallel particle passes plane point of intersection points of contact polar pole prove radical axis radius of curvature ratio rectangle rectangular hyperbola respectively right angles roots self-conjugate sin² sin³ straight line joining subtends a right tangents drawn tetrahedron triangle ABC velocity vertex vertical
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