Solutions of the Cambridge Senate-house Problems and Riders for the Year 1875Sir George Greenhill Macmillan and Company, 1876 - 236 páginas |
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Página 5
... tangent at A parallel to OE . Let the straight line through A ( fig . 7 ) parallel to OD meet OE in F , and draw PM parallel to OE to meet AF in M. By similar triangles PM OF : AP : AB :: AP : AC :: AM : AF ; therefore the locus of P is ...
... tangent at A parallel to OE . Let the straight line through A ( fig . 7 ) parallel to OD meet OE in F , and draw PM parallel to OE to meet AF in M. By similar triangles PM OF : AP : AB :: AP : AC :: AM : AF ; therefore the locus of P is ...
Página 6
Sir George Greenhill. 10. In a central conic the tangent makes equal angles with the focal distances , and the sum or ... tangents to a conic section drawn from a point subtend equal angles at either focus . If PP ' be a chord of a conic ...
Sir George Greenhill. 10. In a central conic the tangent makes equal angles with the focal distances , and the sum or ... tangents to a conic section drawn from a point subtend equal angles at either focus . If PP ' be a chord of a conic ...
Página 7
... tangent line drawn from any point on the curve of section to the sphere will bear the same constant ratio to the distance of the point from the line of intersection of the plane section and the plane of the circle of contact of the ...
... tangent line drawn from any point on the curve of section to the sphere will bear the same constant ratio to the distance of the point from the line of intersection of the plane section and the plane of the circle of contact of the ...
Página 13
... tangents of the angles are in harmonical progression . If a " -b " -b " - c2 , = sin Asin B = sin'B - sin " C , = sin ( B − C ) sin ( B + C ) , sin ( A – B ) sin ( A + B ) - - sin ( AB ) sin C = sin ( B - C ) sin A ; therefore ...
... tangents of the angles are in harmonical progression . If a " -b " -b " - c2 , = sin Asin B = sin'B - sin " C , = sin ( B − C ) sin ( B + C ) , sin ( A – B ) sin ( A + B ) - - sin ( AB ) sin C = sin ( B - C ) sin A ; therefore ...
Página 27
... tangent to which at any point will be parallel to the corresponding line of floatation . If we draw normals from the centre of inertia of the lamina to this last ellipse , these normals will be vertical in the positions of equilibrium ...
... tangent to which at any point will be parallel to the corresponding line of floatation . If we draw normals from the centre of inertia of the lamina to this last ellipse , these normals will be vertical in the positions of equilibrium ...
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Solutions of the Cambridge Senate-House Problems and Riders for the Year 1875 George Greenhill Sin vista previa disponible - 2016 |
Términos y frases comunes
apse line Arabic numbers axes axis Cambridge centre of inertia circle coefficient conic section coordinates cos² cose cosec Crown 8vo curvature curve density diameter differential equation distance dx dy dz dx² Edition electricity ELEMENTARY TREATISE ellipse ellipsoid equal equations of motion equilibrium Extra fcap Fellow of St fixed fluid force given GREEK harmonic Hence hyperbola hypocycloid integral intersect J. P. MAHAFFY John's College late Fellow LATIN length lines of curvature liquid lunar precession magnets middle points normal numerous Illustrations orbit Owens College parabola parallel particle perpendicular plane polar pressure prism Professor prove radius ratio refracting right angles Roman numbers School shew sin sin sin sin² sphere straight line surface tangent triangle ABC Trinity College velocity vertical
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