Solutions of the Cambridge Senate-house Problems and Riders for the Year 1875Sir George Greenhill Macmillan and Company, 1876 - 236 páginas |
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Página 7
... sphere and cone . The rider is proved incidentally in the book work . ( If O be the centre of the sphere and OD be drawn per- pendicular to the plane of the section , it can easily be shewn that the length of any tangent line from a ...
... sphere and cone . The rider is proved incidentally in the book work . ( If O be the centre of the sphere and OD be drawn per- pendicular to the plane of the section , it can easily be shewn that the length of any tangent line from a ...
Página 21
... sphere whose mass is e impinge with velocity v on the sphere whose mass is e1 . Let v ' , v " be the respec- tive velocities of the spheres after impact . or The whole momentum being unchanged +1 e " v = e'v ' + e2 + 1v " , v = v ' + ev ...
... sphere whose mass is e impinge with velocity v on the sphere whose mass is e1 . Let v ' , v " be the respec- tive velocities of the spheres after impact . or The whole momentum being unchanged +1 e " v = e'v ' + e2 + 1v " , v = v ' + ev ...
Página 22
Sir George Greenhill. that is to say , each sphere acquires the velocity of the sphere which struck it , and the velocity of the latter is reduced in ratio 1 e 1 . Hence the final kinetic energy of the system is } { ( 1 — e ) 3 u2 + e ...
Sir George Greenhill. that is to say , each sphere acquires the velocity of the sphere which struck it , and the velocity of the latter is reduced in ratio 1 e 1 . Hence the final kinetic energy of the system is } { ( 1 — e ) 3 u2 + e ...
Página 31
... spherical refracting surface . A hollow globe of glass has a speck on its interior surface , if this be observed from a point outside the sphere on the opposite side of the centre , prove that the speck will appear nearer than it really ...
... spherical refracting surface . A hollow globe of glass has a speck on its interior surface , if this be observed from a point outside the sphere on the opposite side of the centre , prove that the speck will appear nearer than it really ...
Página 32
... sphere ; P , P , the foci after the first and second refractions ; therefore 2 theefore 1 μ μ 1 - = OP " t t 1 OP1 - μ OP2 μ OP = 2 = AP = t - OP μ - 1 2t 3μ - 1 2t μ - 1 = ite 3μ - 1 ix . If a ray of light pass in a principal plane ...
... sphere ; P , P , the foci after the first and second refractions ; therefore 2 theefore 1 μ μ 1 - = OP " t t 1 OP1 - μ OP2 μ OP = 2 = AP = t - OP μ - 1 2t 3μ - 1 2t μ - 1 = ite 3μ - 1 ix . If a ray of light pass in a principal plane ...
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Solutions of the Cambridge Senate-House Problems and Riders for the Year 1875 George Greenhill Sin vista previa disponible - 2016 |
Términos y frases comunes
apse line Arabic numbers axes axis Cambridge centre of inertia circle coefficient conic section coordinates cos² cose cosec Crown 8vo curvature curve density diameter differential equation distance dx dy dz dx² Edition electricity ELEMENTARY TREATISE ellipse ellipsoid equal equations of motion equilibrium Extra fcap Fellow of St fixed fluid force given GREEK harmonic Hence hyperbola hypocycloid integral intersect J. P. MAHAFFY John's College late Fellow LATIN length lines of curvature liquid lunar precession magnets middle points normal numerous Illustrations orbit Owens College parabola parallel particle perpendicular plane polar pressure prism Professor prove radius ratio refracting right angles Roman numbers School shew sin sin sin sin² sphere straight line surface tangent triangle ABC Trinity College velocity vertical
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