Solutions of the Cambridge Senate-house Problems and Riders for the Year 1875Sir George Greenhill Macmillan and Company, 1876 - 236 páginas |
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... given by a candidato in the Examination . By the new regulations for the Examination several new subjects have been introduced , which have not been treated of in preceding collec- tions of Senate - House Solutions . Complete solutions ...
... given by a candidato in the Examination . By the new regulations for the Examination several new subjects have been introduced , which have not been treated of in preceding collec- tions of Senate - House Solutions . Complete solutions ...
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Sir George Greenhill. Complete solutions of the questions on the higher subjects have been given in all cases where it was felt that a reference to the Text - books in ordinary use was not sufficient . An apology must be given for the ...
Sir George Greenhill. Complete solutions of the questions on the higher subjects have been given in all cases where it was felt that a reference to the Text - books in ordinary use was not sufficient . An apology must be given for the ...
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... given straight line describe a segment of a circle which shall contain an angle equal to a given rectilineal angle . Through a fixed point O any straight line OPQ is drawn cutting a fixed circle in P and Q , and upon OP and OQ as chords ...
... given straight line describe a segment of a circle which shall contain an angle equal to a given rectilineal angle . Through a fixed point O any straight line OPQ is drawn cutting a fixed circle in P and Q , and upon OP and OQ as chords ...
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... Given a focus , the length of the transverse axis and that the second focus lies on a fixed straight line , prove that the conic will touch two fixed parabolas having the given focus for focus . If S ( figs . 9 and 10 ) be the given ...
... Given a focus , the length of the transverse axis and that the second focus lies on a fixed straight line , prove that the conic will touch two fixed parabolas having the given focus for focus . If S ( figs . 9 and 10 ) be the given ...
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... given that log , e = 43429 . The result is n = 425.6353 correct to four places of decimals , for generally log1 ( n + 8 ) - log1n = where μloge is the modulus . 10 μδ · + ... n μδ If 8 is so small that does not come 11—4 ] 11 AND RIDERS .
... given that log , e = 43429 . The result is n = 425.6353 correct to four places of decimals , for generally log1 ( n + 8 ) - log1n = where μloge is the modulus . 10 μδ · + ... n μδ If 8 is so small that does not come 11—4 ] 11 AND RIDERS .
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Solutions of the Cambridge Senate-House Problems and Riders for the Year 1875 George Greenhill Sin vista previa disponible - 2016 |
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apse line Arabic numbers axes axis Cambridge centre of inertia circle coefficient conic section coordinates cos² cose cosec Crown 8vo curvature curve density diameter differential equation distance dx dy dz dx² Edition electricity ELEMENTARY TREATISE ellipse ellipsoid equal equations of motion equilibrium Extra fcap Fellow of St fixed fluid force given GREEK harmonic Hence hyperbola hypocycloid integral intersect J. P. MAHAFFY John's College late Fellow LATIN length lines of curvature liquid lunar precession magnets middle points normal numerous Illustrations orbit Owens College parabola parallel particle perpendicular plane polar pressure prism Professor prove radius ratio refracting right angles Roman numbers School shew sin sin sin sin² sphere straight line surface tangent triangle ABC Trinity College velocity vertical
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