Dividing numerator and denominator by p-q, we obtain Dividing numerator and denominator by x-2, we find x2 (3x+2) 4x2-3x+2* 43. Divide denominator by x; then 4x3- 9x2+14x-3)3x-6x3+ 11x2 - 4x+6(-2-8x 8x3+ 18x3- 28x+6 Dividing numerator and denominator by x2 - 2x+3, we find 2x4+x3- 2x2 - 4x-3) 2x5 - x4 - 203- x2. x-3(x-1 2x5+ x4 - 2x3 - 4x2 - 3x - 2x4x3+3x2+2x-3 x2+2x-3 x2+ 2x-3 3x2+2 (4x-1) x 2x3+x2-2x-6) 2x4+x3- 2x2-4x-3(x 2x1+x3- 2x2-6x 44. Dividing numerator and denominator by 2x - 3, we find 45. Divide numerator by 2; then 2x1 – 3x3y +9xy3+4y1) 10x+17x3y - 11xу3- 4y (5 10x+- 15x3y+45xy3 +20y1 8y) 32x3y – 56xу3 — 24y1 4x3 – 7xу2 – 3y3) 2x1 – 3x3y + 9xy3 + 4y1 2x2+3xy + y2) 2x2 - 3x3y+9xу3 + 4y1 (x2 - 3xy+4y2 2x+3x3y + x2y2 - 6x3у- x2y2+ 9xy3+4y1 8x2y2+12xy3+4ya 8x2y2+12xy3 + 4y1 D. A. K. Dividing numerator and denominator by 2x2+3xy+y2, we obtain 2x2-6xy+8y2 5x2+ xy-4y2° 7 Dividing the two expressions by x-4, we obtain x 2 and x-4; hence L. C. M. is (x-2) (x − 4)2. 2. Dividing the two expressions by x+12, we obtain x-7 and x+9; hence L. C. M. is (x+12) (x − 7) (x+9). 3. Dividing the two expressions by x-1, we obtain 3x-4 and 6x-4; hence L. C. M. is (x-1) (3x-4) (6x-4). Dividing the two expressions by 2x-5, we obtain x-1 and 3x-4; hence L. C. M. is (2x – 5) (x − 1) (3x – 4). |