Key to Exercises in EuclidMacmillan and Company, 1880 - 114 páginas |
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Página 1
... right angles at the point 0 ; so that 40 is equal to OB , CO is equal to OD , and the angles at O are right angles . In CD take any point E , and join EA anl EB : then EA shall be equal to EB . For AO is equal to BO by hypothesis ; EO ...
... right angles at the point 0 ; so that 40 is equal to OB , CO is equal to OD , and the angles at O are right angles . In CD take any point E , and join EA anl EB : then EA shall be equal to EB . For AO is equal to BO by hypothesis ; EO ...
Página 2
... angle ADC is bisected by BD ; and also that the angles BAD and BCD are bisected by AC . 12. Let there be two isosceles triangles ACB , ADB on the same base AB , and on opposite sides of it . Join CD ; then CD shall bisect AB at right angles ...
... angle ADC is bisected by BD ; and also that the angles BAD and BCD are bisected by AC . 12. Let there be two isosceles triangles ACB , ADB on the same base AB , and on opposite sides of it . Join CD ; then CD shall bisect AB at right angles ...
Página 3
... angle BAC be bisected by AD , and the angle BAG by AE : the angle DAE shall be a right angle . Since the angle BAD is half the angle BAC , and the angle BAE is half the angle BAG , the two angles BAD and BAE together are half the two angles ...
... angle BAC be bisected by AD , and the angle BAG by AE : the angle DAE shall be a right angle . Since the angle BAD is half the angle BAC , and the angle BAE is half the angle BAG , the two angles BAD and BAE together are half the two angles ...
Página 5
... angle A of a triangle draw DE perpendicular to the side AB , and DF perpendicular to the side AC . Then in the triangles DAE and DAF , the side DA is common ; the angle DAE is equal to the angle DAF , by hypothesis ; and the right angles ...
... angle A of a triangle draw DE perpendicular to the side AB , and DF perpendicular to the side AC . Then in the triangles DAE and DAF , the side DA is common ; the angle DAE is equal to the angle DAF , by hypothesis ; and the right angles ...
Página 6
... right angles , and this straight line will be bisected at O because O is equidistant from the parallels , by hypothesis . Therefore by Exercise 36 the straight lines AB and DC are bisected at 0. Thus in the two triangles AOC , BOD the ...
... right angles , and this straight line will be bisected at O because O is equidistant from the parallels , by hypothesis . Therefore by Exercise 36 the straight lines AB and DC are bisected at 0. Thus in the two triangles AOC , BOD the ...
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ABCD AC and BD AC is equal angle ABC angle ACB angle BAC angle CAB bisects the angle Cambridge centre chord circle described circumference Crown 8vo describe a circle diameter draw a straight Edition equal to BC equal to four equal to half equal to twice equiangular Euclid Exercise 176 Extra fcap fcap fore given circle given point given straight line greater half a right half the angle Hence Let ABC meeting BC middle point Owens College parallel to BC parallelogram perpendicular plane Professor quadrilateral radius equal rectangle rhombus right angles segment shewn side BC square on BC straight line parallel suppose tangent touch the circle triangle ABC twice the angle twice the rectangle twice the squares
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