 | Endless amusement - 1825 - 226 páginas
...into six parts, each containing one pin. Cut off the upper circular part, containing two of the pins, then, by changing the position of the piece, another...horse-shoe into six portions, each containing one pin. PROBLEM X. Place ten halfpence in a row upon a table; then taking up any one of the series, place... | |
 | 1844 - 480 páginas
...off the upper circular part, containing two of the pins, and by changing the position of the pieces, another cut will divide the horse-shoe into six portions, each containing one pin. 9. XIX make nineteen ; therefore, if you take I away, XX must remain. 10. A Shoe. 11. Her Son.... | |
 | 1850 - 484 páginas
...off the upper circular part, containing two of the pins, and by changing the position of the pieces, another cut will divide the horse-shoe into six portions, each containing one pin. 9. XIX make nineteen; therefore, if you take I away, XX must remain. 10. A Shoe. 11. Her Son.... | |
 | Charles Henry Bennett - 1861 - 142 páginas
...off the upper circular part, containing two of the pins, and by changing the position of the pieces, another cut will divide the horse-shoe into six portions, each containing one pin. S. XIX make nineteen ; therefore, if you take I away, XX must remain. 10. A Shoe. 11. Her Son.... | |
 | Frank Bellew - 1870 - 330 páginas
...and mark on it the places for the nails as represented in the subjoined sketch. The puzzle is how, with two cuts to divide it into six parts, each part...one nail. The next trick is of a slightly different character. •Cut two pieces of card like those represented in the •diagram, and place them in the... | |
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The puzzle is with two cuts to divide it into six parts, each part containing one nail. Of course you cannot do it ; we could not do it ourselves, and had to get the white mice to show us the way. Somehow or another we never can find out anything with... 