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EXAMPLES XIII.

√3+tan 40° +tan 80° = √√3. tan 40°. tan 80°.
tan 20° + tan 40° + √3 tan 20° tan 40° = √√3.

cos A cos (B+ C) – cos B cos (A + C) = sin (A – B) sin C.

sin A cos (B+ C) – sin B cos (A + C) = sin (4 – B) cos C. If A + B + C is an odd multiple of π

sin2 B + sin2 C = sin2 A + 2 cos A sin B sin C.

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cos (a + B) + sin (a − ẞ) = 2 sin (‡π + a) cos (†π + ß).

sin a + sin ẞ + sin y − sin (a + B + y)

= 4 sin 1⁄2 (ẞ + y) sin 1⁄2 (y + a) sin § (a + ß).

cos a + cos ẞ + cos y + cos (a + B + y)

= 4 cos (B+y) cos 1 (y + a) cos 1 (a + B).

sin a + sin ß − sin y − sin (a + ß − y)

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sin (ẞ + y − a) + sin (y + a − ß) + sin (a + ß − y)

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- sin (a+B+y)= 4 sin a sin ẞ sin y. cos (B+ y− a) + cos (y + a − ẞ) + cos (a + B − y) + cos (a + B + y) = 4 cos a cos ẞ cos y.

cos2 x + cos2 y + cos2 z + cos2 (x + y + z)

=

2 {1 + cos (y + z) cos (z+x) cos (x + y)}.

sin2 x + sin2 y + sin2 z + sin2 (x + y + z)

= 2 {1 — cos (y + z) cos (≈ + x) cos (x + y)}.

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18.

sin a sin (ẞ− y) + sin ẞ sin (y − a) + sin y sin (a – ẞ) = 0. 19. sin (a+ẞ+y+d)

= cos a cos ẞ cos y cos d (tan a + tan ß + tan y + tan 8)

20.

sin a sin ẞ sin y sin 8 (cot a + cot ẞ + cot

γ
+ cot 8).

cos (SA) cos (S-B) cos (S-C) cos (S— D) + sin (S-A) sin (S-B) sin (S-C) sin (SD)

if

=cos A cos B cos C cos D+ sin A sin B sin C sin D

2S = A + B + C + D.

21. If a right-angle is divided into three parts whose tangents are lp, mp, np;

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26.

27.

=

2 tan A sec2 B
1-tan2A tan2 B*

2 tan B sec2 A

1- tan2 A tan2 B*

2 cot A cosec2 B
cot B-cot2 A

2 cot B cosec2 A

cot2 B-cot2 A

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2 sec A sec B

sec (A + B) + sec (A – B) = sec2 4 + sec2 B – sec2 A sec2 B

2 cox A cox B

sec (A + B) – sec (A – B) = cox2 A cox2 B — cox2 A — cox2 B

If A, B, C are the angles of a triangle, prove 28-33: sin A sin B sin C

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sin A cos B cos C + sin B cos C cos A+ sin C cos A cos B. 1 + cos A cos B cos C

= cos A sin B sin C + cos B sin C sin A + cos C sin A sin B. tan A tan B tan C tan A+ tan B+ tan C.

=

31. cot B cot C + cot C cot A + cot A cot B=1.

32. cos A cos B cos Csin A sin B cos C

+ sin B sin C cos A+ sin C sin 4 cos B.

33. tan B tan C + tan C tan A+ tan A tan B=1.

34. If A, B, C, D are the angles of a quadrilateral,
tan Atan B+tan C + tan D

(i)

cot A + cot B + cot C + cot D=tan A tan B tan C'tan D, (ii) sin A sin B cos C cos D + ...

= cos A cos B cos C cos D + sin A sin B sin C sin D – 1. 35. If 0, 4, are the angles which any straight line, in the plane of the triangle ABC, makes with BC, CA, AB respectively,

then

then

36.

37.

then

(i) a2 sin (Þ +4 − 0) + b2 sin († + 0 − p) + c2 sin (0 + 0 − 4) +2bc sin 0 + 2ca sin & + 2ab sin ↓ = 0.

(ii) a2 cos (+ 4 − 0) + b2 cos (4 + 0 − p) + c2 cos (0 + − ¥) +2bc cos 0 + 2ca cos &+2ab cos &= 0.

If sin sin a sin (ø + a − ß) = sin ø sin (a + ß) sin (a + 0), sin & sin a sin (0+ a + B) = sin 0 sin (a – ẞ) sin (a + ¢).

If cos e cos a cos (+ a − ẞ) = cos o sin (a + ẞ) sin (a + 0), cos & cos a cos (0+ a + ẞ) = cos 0 sin (a – ẞ) sin (a + ).

38. In a triangle right-angled at C,

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and if ẞ and y are unequal, then each member

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and

cot 0

=

43.

sin (ẞ + y) sin (y + a) sin (a + ß)

cos (B+y) cos (y + a) cos (a + ß) + sin2 (a + ß + y) *

If cos (a + B + y) − sin (a + B + y)

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then either a or ẞ or y is of the form (n − 1)π.

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2 sin 0 sec3 0

1- tan2 a tan2 ('

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sin (A + B) = sin A cos B + cos A sin B ......
cos (A + B) = cos A cos B- sin A sin B

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2.69

.(1),

..(2),

(3).

.(4).

...(5).

.(6).

353. Now we may observe that

(cos A + sin A)2 = cos2 A + 2 sin A cos A + sin2 A,

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Comparing these expansions with the above formulæ (4), (5), (6), we see that

and

first term - last term of (cos A + sin A)2 = cos 2A,

middle term

of (cos A + sin A)2 = sin 24,

first term – last term of (1 + tan A)2 = den. of tan 24,

middle term of

(1 + tan 4)2 = num. of tan 24.

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