A Series of Chemical Problems with Key for Use in Colleges and SchoolsMacmillan, 1891 - 139 páginas |
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... Formula from Percentage Compo- sition . Formulæ of Minerals To Calculate the Percentage Composition of a Compound from its Formula . Chemical Equations ; to Calculate the Amount of Material Required to Produce a Given Weight of any ...
... Formula from Percentage Compo- sition . Formulæ of Minerals To Calculate the Percentage Composition of a Compound from its Formula . Chemical Equations ; to Calculate the Amount of Material Required to Produce a Given Weight of any ...
Página 22
... formula - 0'0012932 . ( V v ) . H ( 1 + 0 * 00367 t ) . P ' - P + 1 + 000367 . Z [ V ( 1 + k T ) − v . 27 . - 760 H 1 + 000367 . t ] · 760. ( 1 + 0 ° 00367 . T ) . 00012932 if hydrogen be taken as unity o'0012932 is replaced by 0 ...
... formula - 0'0012932 . ( V v ) . H ( 1 + 0 * 00367 t ) . P ' - P + 1 + 000367 . Z [ V ( 1 + k T ) − v . 27 . - 760 H 1 + 000367 . t ] · 760. ( 1 + 0 ° 00367 . T ) . 00012932 if hydrogen be taken as unity o'0012932 is replaced by 0 ...
Página 24
... formula is D = P ' P + Vnt ( V – v ) nT = 14'436 - · ..D = ( 25'0122 — 24 ° 4722 ) + ( 169 * 50 * 001252788 ) = ( 1695 125 ) .0'000722-788 62 05400 +02128 157.0000722.78814 ° 436 07528.14436 . 157.0000722.788 . 95'62 . From the more ...
... formula is D = P ' P + Vnt ( V – v ) nT = 14'436 - · ..D = ( 25'0122 — 24 ° 4722 ) + ( 169 * 50 * 001252788 ) = ( 1695 125 ) .0'000722-788 62 05400 +02128 157.0000722.78814 ° 436 07528.14436 . 157.0000722.788 . 95'62 . From the more ...
Página 36
... formula of a com- pound , divide the percentage amount of each constituent by its corresponding atomic weight ... formula . = The atomic weight of carbon = 16 . = 12 ; that of oxygen Then C : 27.273 = = 2'2727 12 0 = 36 DEDUCTION OF ...
... formula of a com- pound , divide the percentage amount of each constituent by its corresponding atomic weight ... formula . = The atomic weight of carbon = 16 . = 12 ; that of oxygen Then C : 27.273 = = 2'2727 12 0 = 36 DEDUCTION OF ...
Página 37
... formula of the compound is CO2 2. A compound of hydrogen and nitrogen was found to possess the following percentage composition . Calculate its formula . Nitrogen Hydrogen . · " · 82.353 17.647 100'000 The atomic weight of N = 14 , and ...
... formula of the compound is CO2 2. A compound of hydrogen and nitrogen was found to possess the following percentage composition . Calculate its formula . Nitrogen Hydrogen . · " · 82.353 17.647 100'000 The atomic weight of N = 14 , and ...
Otras ediciones - Ver todas
A Series of Chemical Problems with Key for Use in Colleges and Schools Sir T. E. (Thomas Edward) Thorpe Sin vista previa disponible - 2012 |
SERIES OF CHEMICAL PROBLEMS W/ T. E. (Thomas Edward) Sir Thorpe, 1845 Sin vista previa disponible - 2016 |
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A. S. WALPOLE A. W. VERRALL absorption acetic analysis ARITHMETIC Assistant Master atomic weight barometer BEGINNERS Calculate calorific Cambridge carbon dioxide cent chloride CO₂ coefficient combustion contained Crown 8vo cubic centimetres dens Edited ELEMENTARY TREATISE ELEMENTS English Exercises F.R.S. Illustrated Fcap Fellow of Trinity following numbers formula freezing-point G. E. FASNACHT gases GEOGRAPHY GEOMETRY GRAMMAR grams GREEK H₂ H₂O hence HISTORY hydrochloric acid hydrogen Introduction and Notes ISAAC TODHUNTER J. P. MAHAFFY JOHN kilogram kilos LATIN Lecturer liquid litres Litt.D LL.D M.A. BOOK M.A. Cr MACMILLAN'S Maps Mathematics measured mercury metres millimetres mixture molecular weight monoxide nitrogen Owens College oxide oxygen Phosphorus PHYSICS potassium potassium chlorate preparation Press pressure PRIMER Prof Professor of Chemistry relative density revised and enlarged School silver sodium solution specific heat sulphuric acid temperature TEXT-BOOK Translated Trinity College vapour density volume Weight of substance دو وو
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